2x^2(2-20)=x^2+-16

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Solution for 2x^2(2-20)=x^2+-16 equation: 



2x^2(2-20)=x^2+-16

We move all terms to the left:

2x^2(2-20)-(x^2+-16)=0

We add all the numbers together, and all the variables

2x^2(-18)-(x^2+-16)=0

We use the square of the difference formula

2x^2(-18)-(x^2-16)=0

We get rid of parentheses

2x^2(-18)-x^2+16=0

We add all the numbers together, and all the variables

-1x^2+2x^2(-18)+16=0

We move all terms containing x to the left, all other terms to the right

-1x^2+2x^2(-18)=-16

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